Assume that the box contains 3 defective widgets and 9 acceptable widgets. There are 3 inspectors, each of wh?

Each inspector has a 3 in 12 (3/12) chance of finding a defective widget. To find if any 1 of them find a defective widget you add their chances together. Reduce the 3 in 12 down to a 1 in 4 chance. Inspector 1 OR Inspector 2 OR Inspector 3 finding a defective widget is equal to 1/4+1/4+1/4 or 3/4 which equates to a 75% chance of finding a defective widget.